9m^2=169

Solution for 9m^2=169 equation:

9m^2=169

We move all terms to the left:

9m^2-(169)=0

a = 9; b = 0; c = -169;
Δ = b2-4ac
Δ = 02-4·9·(-169)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6084}=78$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-78}{2*9}=\frac{-78}{18}
=-4+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+78}{2*9}=\frac{78}{18}
=4+1/3
$